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STUDY GUIDES: TEST 1 | TEST 2 | TEST 3
Chapter: 1 | 4 | 5 | 6 | 7
LOGIC WORKBOOK A COMPANION TO HURLEY John Chiappone
7.1 NATURAL DEDUCTION IN PROPOSITIONAL LOGIC
RULES OF IMPLICATION
NOTE: The answers are in white text. Highlight the text to see the answers.
MODUS PONENS (MP):
p > q
p
_____
q
Proofs Using Modus Ponens:
(1)
1. p > q
2. p / q
3. q 1, 2 mp
(2)
1. p
2. p > q / q
3. q 2, 1 mp
(3)
1. r > t
2. r / t
3. t 1, 2 mp
(4) 1. (y ≡ u) > o The main operator is > .
2. y ≡ u / o
3. o 1, 2 mp
(5)
1. x > p
2. (x > p) > r / r
3. r 2, 1 mp
(6) 1. u v y
2. (u v y) > (x v t) What is the main operator? >
3. w • s / x v t
4. x v t 2, 1 mp
(7)
1. [(o ≡ p) • x] > (s • u) What is the main operator? >
2. (o ≡ p) • x
3. ~y v t / s • u
4. s • u 1, 2 mp
(8)
1. m v ~m
2. [(m v y) v t] > [(s > p) • x]
3. (m v y) v t / (s > p) • x
4. (s > p) • x 2, 3 mp
(9)
1. p > [(x v y) v z]
2. ~r • y
3. ~u
4. p / (x v y) v z
5. (x v y) v z 1, 4 mp
MODUS TOLLENS (MT):
~q
______
~p
Proofs Using Modus Tollens:
(1) 1. p > q
2. ~q / ~p
3. ~p 1, 2 mt
1. ~y
2. x > y / ~x
3. ~x 2, 1 mt
(3) 1. m > ~w
2. ~~w / ~m
3. ~m 1, 2 mt
(4) 1. ~u > p
2. ~p / ~~u
3. ~~u 1, 2 mt
(5) 1. x > (o • m)
2. ~(o • m) / ~x
3. ~x 1, 2 mt
(6) 1. (p ≡ o) > u
2. ~u / ~(p ≡ o)
3. ~(p ≡ o) 1, 2 mt
(7) 1. (p ≡ o) > (o • m) What is the main operator? >
2. ~(o • m) / ~(p ≡ o)
(8) 1. x > t
2. ~t
3. s > x / ~s
4. ~x 1, 2 mt
5. ~s 3, 4 mt
(9) 1. ~r
2. u > ~~r What is the main operator? >
3. x > p
4. p > u / ~x
5. ~u 2, 1 mt
6. ~p 4, 5 mt
7. ~x 3, 6 mt
Proofs Using Modus Tollens
& Modus Ponens:
1. ~x
2. p > x
3. ~p > q / q
4. ~p 2, 1 mt
5. q 3, 4 mp
1. z > q
2. ~q
3. ~z > p / p
4. ~z 1, 2 mt
5. p 3, 4 mp
(3) 1. p > ~q
2. s > q
3. p / ~s
4. ~q 1, 3 mp
5. ~s 2, 4 mt
(4)
1. x • z
2. (x • z) > r
3. r > ~y
4. q > y / ~q
5. r 2, 1 mp
6. ~y 3, 5 mp
7. ~q 4, 6 mt
1. ~t
2. x > t
3. q > x
4. ~q > r / r
5. ~x 2, 1 mt
6. ~q 3, 5 mt
7. r 4, 6 mp
(6)
1. ~m > w
2. m > z
3. z > t
4. ~t / w
5. ~z 3, 4 mt
6. ~m 2, 5 mt
7. w 1, 6 mp
Pure Hypothetical Syllogism (HS):
q > r _____
p > r
Proofs Using Hypothetical Syllogism:
1. P > S
2. S > Q / P > Q
3. P > Q 1, 2 HS
1. D > S
2. S > T
3. T > U / S > U
4. S > U 2, 3 HS
1. (A • B) > C
2. C > D / (A • B) > D
3. (A • B) > D 1, 2 HS
1. W > Q
2. S > W / S > Q
3. S > Q 2, 1 HS
1. (A v C) > S
2. D > C
3. E > (A v C) / E > S
4. E > S 2, 1 HS
1. (Q > X) > (A• N)
2. (A • N) > P / (Q > X) > P
3. (Q > X) > P 1, 2, HS
1. [(A • S) > T] > (O v B)
2. W > [(A • S) > T] / W > (O v B)
3. (O v B) 2, 1 HS
Proofs Using Hypothetical Syllogism and Modus Ponens:
1. P > C
2. C > L
3. P / L
4. P > L 1, 2 HS
5. L 4, 3 MP
1. A > B
2. B > C
3. (A > C) > D / D
4. A > C 1, 2 HS
5. D 3, 4 MP
1. H > P
2. P > (B > M)
3. B
4. B > H / M
5. H > (B > M) 1, 2 HS
6. H 4, 3 MP
7. B > M 5, 6 MP
8. M 7, 3 MP
1. C > T
2. T > D
3. B > C
4. B / D
5. C > D 1, 2 HS
6. C 3, 4 MP
7. D 5, 6 MP
(5) 1. F > (J > X)
2. Y > F
3. Y
4. J / X
5. F 2, 3 MP
6. J > X 1, 5 MP
or
5. Y > (J > X) 2, 1 HS
6. J > X 3, 5 MP
7. X 6, 4 MP
Note: A proof that takes less steps is said to be more elegant.
1. S • T
2. C
3. (S • T) > G
4. G > (C > K) / K
5. (S • T) > (C > K) 3, 4 HS
6. C > K 5, 1 MP
7. K 6, 2 MP
1. E > F
2. Y > E
3. (Y > F) > (H > S)
4. (H > S) > (I > P)
5. I / P
6. Y > F 2, 1 HS
7. (Y > F) > (I > P) 3, 4 HS
8. I > P 7, 6 MP
9. P 8, 5 MP
DISJUNCTIVE SYLLOGISM (DS):
p v q p v q
~p ~q
______ _____
q p
Proofs Using Disjunctive Syllogism:
1. ~P
2. P v Q / q
3. Q 2, 1 DS
1. s v t
2. ~s / t
3. t 1, 2 ds
1. m v u
2. ~u / m
3. m 1, 2 ds
1. (x • p) v t
2. ~t / x • p
3. x • p 1, 2 ds
1. (x v u) v t
2. ~(x v u) / t
1. y v (t > p)
2. ~(t > p) / y
3. y 1, 2 ds
1. (u v t) v (x > z)
2. ~(u v t) / x > z
3. x > z 1, 2 ds
2. ~(x > z) / u v t
3. u v t 1, 2 ds
1. m v ~t
2. ~m
3. t v y / y
4. ~t 1, 2 ds
5. y 3, 4 ds
(10)
1. o v ~u
2. u v r
3. ~o / r
4. ~u 1, 3 ds
5. r 2, 4 ds
(11)
1. y v m
2. t v ~y
3. ~m / t
4. y 1, 3 ds
5. t 2, 4 ds
Proofs Using Disjunctive Syllogism and Modus Ponens:
(1) 1. ~P
2. P v Q
3. Q > Z / Z
4. Q 2, 1 DS
5. Z 3,4 MP
1. D > ~X
2. D
3. X v N / N
4. ~X 1, 2 MP
5. N 3, 4 DS
1. (I • B) v (E v G)
2. ~(I • B) What is the main operator? ~
3. ~E
4. G > Y / Y
5. E v G 1, 2 DS
6. G 5, 3 DS
7. Y 4, 6 MP
1. A V C
2. ~C
3. ~B
4. A > (B v D) / B > D
5. A 1, 2 DS
6. B > D 3, 4 MP
7. D 4, 6, 3 DS
1. (P • Q) V (D > F) What is the main operator? V
2. ~(D > F)
3. (P • Q) > T / T
4. P • Q 1, 2 DS
5. T 3, 4 P
1. [(F v G) V (T v Y)] > (Z v F) What is the main operator? >
2. ~[(F v G) V (T v Y)]
3. ~Z / F
4. Z v F 1, 2 MP
5. F 3, 4 DS
Proofs Using Disjunctive Syllogism, Modus Ponens, and Modus Tollens:
1. P > ~Q
2. P
3. Q v ~W
4. C > W / ~C
5. ~Q 1, 2 MP
6. ~W 3, 5 DS
7. ~C 4, 6 MT
1. S v T
2. ~S
3. T > ~(K • F) What is the main operator? >
4. (K • F) v (R > S) / ~R
5. T 1, 2 DS
6. ~(K • F) 3, 5 MP
7. R > S 4, 5 DS
8. ~R 7, 2 MT
1. C > B
2. ~ B
3. ~C > (B v D) / D
4. ~C 1, 2 MT
5. B v D 3, 4 MP
6. D 5, 2 DS
1. (B v C) v (A v ~N)
2. (B v C) > S
3. ~S
4. ~A / ~N
5. ~(B v C) 2, 3 MT
6. A v ~N 1, 5 DS
7. ~N 6, 4 DS
1. R • X
2. C > [E > (B > D)]
3. C
4. E v L
5. ~L
6. ~D / ~B
7. E > (B > D) 2, 3 MP
8. E 4, 5 DS
9. B > D 7, 8 MP
10. ~B 9, 6 MT
Hypothetical Syllogism (HS):
Proofs Using All the Rules:
1. M > P
2. M
3. P > R / M > R
4. M > R 1, 3 HS
1. (X v D) v D
2. H
3. ~D / X
4. X v D 1, 3 DS
5. X 4, 3 DS
(3) 1. (D > S) > (T v W)
2. D > R
3. R > S / T v W
4. D > S 2, 3 HS
5. T v W 1, 4 MP
(4) 1. H > P
2. D > (P > S)
3. D / H > S
4. P > S 2, 3 MP
5. H > S 1, 4 HS
1. G > ~T
2. ~~t
3. ~G > ~F What is the main operator? >
4. F v D / D
5. ~G 1, 2 MT
6. ~F 3,5 MP
7. D 4, 6 DS
1. P > Q
2. Q > S
3. (P > S) > (D > E)
4. ~E
5. ~D > T / T
6. P > S 1, 2 HS
7. D > E 3, 6 MP
8. ~D 7, 4 MT
9. T 5, 8 MP
1. D v C
2. D > B
3. B > S
4. S > U
5. ~C / U
6. D 1, 5 DS
7. D > S 2, 3 HS
8. S 7, 6 MP
9. U 8, 4, 8 MP
1. B v W
2. B > (Y > M)
3. ~W
4. M > Q / Y > Q
5. B 1, 3 DS
6. Y > M 2, 5 MP
7. Y > Q 6, 4 HS
1. ~T
3. D > S
4. ~D > Z / Z
5. ~S 2, 1 MT
6. ~D 3, 5 MT
7. Z 4, 6 MP
1. (T • G) > (X v P)
2. ~P V S
4. T • G / X
5. ~P 2, 3 DS
6. X v P 1, 4 MP
7. X 6, 5 DS
1. A > F
2. F > (T > R)
3. R > S
4. T
5. A / S
6. A > (T > R) 1, 2 HS
7. T > R 6, 5 MP
8. T > S 7, 3 HS
9. S 8, 4 MP
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